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| Subject: | RE: (semi-OT): Correct definition of the DES OFB? |
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| Date: | Sun, 24 Jul 2005 13:16:40 -0400 |
Good day, The best reference for any of the DES Modes of operation is FIPS81 at: http://www.columbia.edu/~ariel/ssleay/fip81/fip81.html You cannot go wrong and it is well explained with illustrations. If you wish to get more details and targeted responses, you could post your questions to CISSP specific mailing list such as the CISSPStudy mailing list at www.cccure.org Visit http://cccure.org/mailman/listinfo/cisspstudy_cccure.org to subscribe. Take care Clement Clément Dupuis, CD President/Security Evangelist/Chief Learning Officer (CLO) CCCure Enterprise Security & Training Inc. CISSP, GCFW, GCIA, Security+, CEH, CCSA, MBNS, MBIS, MBHS, CCSE, ACE Tel: 954 364 8410 (Florida) Tel: 514 907 1671 (Montreal) Tel: 418 907 0263 (Quebec) Fax: 636 773 6328 Maintainer of : The CISSP and SSCP Open Study Guides Web Site http://www.cccure.org The Professional Security Testers Warehouse http://www.professionalsecuritytesters.org
-----Original Message----- From: Saqib Ali [mailto:docbook.xml@gmail.com] Sent: Sunday, July 24, 2005 9:37 AM To: webappsec@securityfocus.com; security-basics@securityfocus.com! Subject: (semi-OT): Correct definition of the DES OFB? Hello All, I was reading the CISSP Exam Guide by Shon Harris (2nd Edition). She gives the following definition for DES in the OFB (Output Feedback) Mode. "...if DES is working in Output Feedback (OFB) Mode, it is functioning like a stream cipher by generating a stream of random binary bits to be combined with the plaintext to create ciphertext. The ciphertext is fed back to the algorithm to form a portion of the next input to encrypt the next stream of bits." (page 486) I thin, the last sentence "The ciphertext is fed back to the algorithm to form a portion of the next input to encrypt the next stream of bits" is incorrect. That is what happen in the Cipher Feeback (CFB) Mode, and NOT theOFB mode. In OFB mode, the "random value" is fed back into the algorithm. i.e. the "Random Value" from the previous operation becomes the IV for the next operation. Am I correct? Can anyone please validate this? Thanks. -- In Peace, Saqib Ali http://www.xml-dev.com/blog/
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