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| Subject: | Re: Re[2]: encryption algs |
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| Date: | Mon, 31 Jan 2005 09:06:52 -0500 |
If you look at the manpage for crypt(): http://www.rt.com/man/crypt.3.html It shows that crypt() takes the lower 7 bits of the plaintext to produce a 56bit key. This produces the "13-letters state" as you put it. So as far as taking the output from a normal implementation of DES and transforming it an output like that of crypt(), I'm not sure its possible. I think you would need to have the plaintext. Is this what you were looking for? Kevin On Fri, 28 Jan 2005 13:41:33 +0300, BoI base <postbase@mail.ru> wrote:
Hello Ghaith, Friday, January 28, 2005, 12:42:53 PM, you wrote: You said, that MD5 has 2 different implementations: NT-MD5 and UNIX-MD5? Maybe there is no difference in 2 algorithms before fixed point (before output)? GN> Sorry, I didn't get your second question. By FIPS-46-3 we have, that result of DES function is 64-bit array. But using unix crypt(3) function (implementation of the same DES algorithm) has 13*8=104-bit result (for example, hash: VF6NabIjwyOI2). I have code for 64-bit DES result. But I need code for receiving 104-bit DES result (unix crypt(3)). -- Best regards, Xanders mailto:postbase@mail.ru
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