It just looks like your query is invalid.
While SQL injection is easier to perform than trying to bring some
strong encryption, it still requires that your SQL is well formed.
In your case, your input string probably does something along the
lines of SELECT col1, col2, FROM Tbl_Foo WHERE item_id=:cItemID
AND 1=1 is the most commonly cited example for SQL Injection because
it will work in almost any situation including the above. However, it
doesn't really get you anywhere interesting, takes a little more than
that to have fun. Unfortunately, lots of people who write or talk
about SQL Injection neglect to mention that you really do need to know
what you're writing (just like script kiddies).
Your statement, SELECT * FROM usr probably returns a lot more columns
than your first query so the UNION will fail. Nothing wrong with the
vulnerability. Just regular SQL syntax error. :-) Try something like
; SELECT * FROM usr
Bottom line is, you gotta have well formed SQL.
joe.
On 1/17/08, Clone <c70n3@yahoo.co.in> wrote:
Hey List
I am pen testing a web app that supplies sql
parameters on the URL something like
http://x.y.z.a/item.php?Id=90
I did blind sql injection by adding AND 1=1 to confirm
the vulnerability.
Now when I do
http://x.y.z.a/item.php?Id=90'
I get
ociparse() [function.ociparse]: OCIParse: ORA-01756:
quoted string not properly terminated in item.php on
line 312
Then I tried (after confirming presence of usr table
name)
http://x.y.z.a/item.php?Id=90%20UNION%20SELECT%20*%20from%20usr;--
and I get the error
ociexecute() [function.ociexecute]: OCIStmtExecute:
ORA-01789: query block has incorrect number of result
columns in dbs.inc on line 44
I know one valid user account in the oracle DB.
Any idea what's the best strategy to move forward?
I'm not getting any further from here so far.
Any advise / helpo would be much appreciated.
Cheers'
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