Hey Alcides,
It would be more helpful if you can provide the actual
code. Are you sure you are watching the EIP values
right after the overflow happens and I mean in asm not
C. The key to understanding BO is to notice how the
stack, EIP and EBP are manipuated for each asm
instruction. "Smashing the stack for fun and profit"
is the quintessential reference for understanding BO.
The basic stack structure is:
[Buffer][EBP/Frame pointer][Return addr/saved
Instruction Ptr][arguments]
You need to account for the Frame pointer/ BP. From
what you say in 3] and 4] either you are not looking
at the what you need to watch for or you are not
reaching till the ret addr. Hope that helps.
Cheers & Chi!!
Amit
--- Alcides <alcides.hercules@gmail.com> wrote:
Hi List,
I was wondering if someone has already done this.
I'm testing a small program written in C, especially
coded for testing
buffer overflow.
In source code, I have assigned char buffer[512]; I
compile with gcc and
run on bash.
As soon as I pass "512" characters as
argument("A"x512--being precise),
the program gives " Segmentation fault (core dumped
)" -->as desired.
1] Using GDB debugger, it has been verified that the
extended
instruction pointer EIP has been overwritten, as
expected.
(EIP-->0x41414141)
2] But, on passing "513" chars. argument, the EIP
becomes 0x0 -->WHY
3]On passing 520 chars. argument, EIP takes 'some'
value and EBP
becomes 0x41414141
4]Thereafter, every increment by 1 --> in input
characters causes EIP to
remain the same as that 'some' value and EBP to take
various incremental
values.
every time, for several unit increments
[I am using: 2.6.21-1.3194.fc7 kernel, i686,
Disabled VA randomization]
Any views that help me understand why EIP becomes
0, are welcome.
Thanks.
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