[Full-disclosure] OpenSSH - System Account Enumeration if S/Key is used

Note to the Moderator: Sorry I send ya a Beta in the first mail :)

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                            Helith - 0815
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Author: Rembrandt
Date: Known since somewhere in 2005
Affected Software: OpenSSH 4.6 <=
                   Proppably everything which is based on OpenSSH
Type: Remote
Type: Enumeration of system accounts

Greets go to: Helith and all affiliated People, t3c0, levent, str0ke,
              The EOF-Crew, rrlf, herm1t, Solar Designer, softxor,
              Packetstorm (Todd, Emerson(Thanks for the Cohiba and beer))
              and others

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OpenSSH is vulnerable to an information leak which allows remote attackers
to gain informations about system accounts, in case S/KEY is used on the system.

If "ChallengeResponseAuthentication" is set to "Yes", which is the default
setting, SH allows the user to login by using S/KEY in the form of 
'ssh userid:skey@hostname'.

The normal behavior for SSH looks like this:

===============================================================================
alucard $ ssh user@somewhere
Permission denied (publickey,keyboard-interactive).
===============================================================================

Passwordauthentication is disabled as you can see.
Now you can test about ChallangeResponseAuthentication.
If it`s enabled it will let you determine the existence of system accounts.

===============================================================================
alucard $ ssh user:skey@somewhere
otp-md5 99 some04578
S/Key Password:

alucard $
===============================================================================

If a account does not exist OpenSSH reacts like exspected.

===============================================================================
alucard $ ssh testuser:skey@somewhere
Permission denied (publickey,keyboard-interactive).
===============================================================================


As you can see clearly OpenSSH discloses the existence of system accounts.
A possible solution for this problem would be to print a fake S/Key-Request
even for non existing users as well as it`s done with the 
Passwordauthentication.

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